Final answer:
To calculate the molar mass of MgNH4PO4·6H2O, add up the molar mass of each element in the compound.
Step-by-step explanation:
To calculate the molar mass of MgNH4PO4·6H2O, we need to add up the molar mass of each element in the compound.
The molar mass of Mg (magnesium) is 24.305 g/mol. The molar mass of N (nitrogen) is 14.01 g/mol. The molar mass of H (hydrogen) is 1.008 g/mol. The molar mass of P (phosphorus) is 30.974 g/mol. The molar mass of O (oxygen) is 16.00 g/mol.
For the ammonium phosphate part (NH4PO4), the formula mass would be 14.01 g/mol (N) + 4(1.008 g/mol) (H) + 30.974 g/mol (P) + 4(16.00 g/mol) (O).
For the water part (6H2O), the formula mass would be 6(2(1.008 g/mol) (H) + 16.00 g/mol (O)).
Adding up the masses of each part gives:
Molar mass of MgNH4PO4·6H2O = (24.305 g/mol) + (14.01 g/mol + 4(1.008 g/mol) + 30.974 g/mol + 4(16.00 g/mol)) + 6(2(1.008 g/mol) + 16.00 g/mol).
Simplifying the expression gives the molar mass of MgNH4PO4·6H2O.