Final answer:
The element with the electron configuration of n=4, l=2, m=1, s=1/2 is Nickel (Ni), as this configuration refers to one of the d-orbital electrons in Nickel's electron configuration 3d84s2.
Step-by-step explanation:
The element with the electron configuration n=4, l=2, m=1, s=1/2 is Nickel (Ni). This particular configuration indicates that it is the 3d84s2 part of Nichel's electron configuration. In the case presented, we are considering one of the 3d electrons, which is in the d-orbital (l=2) with a magnetic quantum number of m=1, indicating which specific d-orbital the electron occupies, and a spin quantum number of s=1/2, corresponding to an electron's spin. Therefore, the correct answer is D. Nickel (Ni).