Question

How many moles of H2O are equivalent to 97.3 grams of H2O? (H = 1.008 g/mol, O = 16.00 g/mol)

A) 0.25 mol
B) 3.05 mol
C) 6.06 mol
D) 97.3 mol

Answer 1

To determine the moles of H2O in 97.3 grams of water, divide the mass (97.3 grams) by the molar mass of water (18.016 g/mol), resulting in approximately 5.40 moles. Option B) 5.40 mol is the closest accurate answer.

Step-by-step explanation:

To find out how many moles of H2O are equivalent to 97.3 grams of H2O, we use the molar mass of H2O as a conversion factor. The molar mass of water (H2O) is calculated by adding the molar masses of hydrogen and oxygen, which are 1.008 g/mol for hydrogen (H) and 16.00 g/mol for oxygen (O).

For water, this calculation is (2 x 1.008 g/mol) + (16.00 g/mol) = 18.016 g/mol. The number of moles can then be found by dividing the mass of the water by its molar mass:

97.3 g / 18.016 g/mol = 5.40 moles of H2O.

Therefore, the closest answer to the given options is: B) 5.40 mol.