Final answer:
The speed of a bungee jumper 10 seconds after jumping in the absence of air friction is -98 m/s, calculated using the formula v = gt with g as -9.8 m/s².
Step-by-step explanation:
The question at hand involves a bungee jumper and the speed they would achieve after falling for 10 seconds in the absence of air friction, with gravity being the only force acting on them. The acceleration due to gravity (g) is a constant at -9.8 m/s2, which means that the speed increases linearly over time when air resistance is neglected. The formula to calculate the speed (v) after a certain time (t) is v = gt. Plugging in the values, we get v = (-9.8 m/s2)(10 s) which equals -98 m/s. The negative sign merely indicates the direction of acceleration is downwards.
Therefore, the speed of the jumper 10 seconds after jumping is -98 m/s, which corresponds to option (B).