Final answer:
The amount of alcohol in a margarita can vary, 3 oz, 2.5 oz, and 2 oz are all typical amounts for different recipes. For the Chemistry question on ethanol: density of a given 75% ethanol solution is 921.4 g/L, and to prepare 3.5L of 2M ethanol, 466.7 mL of the solution is required.
Step-by-step explanation:
The question you've asked about how much alcohol does a margarita typically have is not directly related to the information provided about the ethanol solution. Margaritas are cocktails that contain different ingredients including tequila, which usually has an alcohol content of 40%. The amount of tequila in a margarita can vary based on the recipe, but options a) 3 oz, b) 2.5 oz, and c) 2 oz all represent different possible amounts. To answer your Chemistry homework regarding the 75% ethanol solution:
a. Density of the Ethanol Solution,
Given that the solution contains 15 moles of ethanol per liter, we can calculate the density by using the molar mass of ethanol (C2H5OH, approximately 46.07 g/mol). The mass of ethanol in 1 liter is 15 moles × 46.07 g/mol = 691.05 g. Since this is 75% of the mass of the solution, the total mass of 1 liter of solution is 691.05 g × 100/75 = 921.4 g. Therefore, the density is 921.4 g/L.
b. Preparation of 3.5L of 2M Ethanol Solution,
To prepare a 3.5L solution of 2M ethanol, you would need 7 moles of ethanol (since 2M means 2 moles per liter, and you need 3.5 liters). The initial solution has a concentration of 15M. To find the volume needed from the initial solution, use the equation C1V1 = C2V2 where C1 is the concentration of the initial solution, V1 is the volume of the initial solution needed, C2 is the final concentration, and V2 is the final volume. Plugging in the numbers: 15M × V1 = 2M × 3.5L. Solving for V1 gives V1 = (2M × 3.5L) / 15M = 0.4667L, which is 466.7 mL.