229,516 views
12 votes
12 votes
How do you think the energy at the top of the ramp will compare with the energy at the bottom of the ramp? Why do you think this?

User Richard Tingle
by
3.4k points

1 Answer

25 votes
25 votes

We are asked to compare the energy of a mass at the top of a ramp with the energy at the bottom:

The energy at the top is the gravitational potential energy and is given by:


U=mgh

Where:


\begin{gathered} m=\text{ mass} \\ g=\text{ acceleration of gravity} \\ h=\text{ height} \end{gathered}

The energy at the bottom is kinetic energy and is given by:


K=(1)/(2)mv^2

Where:


v=\text{ velocity}

Due to the principle of conservation of energy, the energy at the top is equal to the energy at the bottom is no energy is lost. Therefore, we have:


U=K

Or:


mgh=(1)/(2)mv^2

How do you think the energy at the top of the ramp will compare with the energy at-example-1
User Erik Ahlswede
by
3.3k points