Question

In the Hardy-Weinberg equation, p² + 2pq + q² = 1. If the dominant allele frequency is 0.8, what percent of the population will be homozygous dominant?

Answer 1

If the dominant allele frequency is 0.8, then 64% of the population will be homozygous dominant (AA) according to the Hardy-Weinberg equation (p²).

Step-by-step explanation:

When the frequency of the dominant allele (represented by p) is 0.8 in the Hardy-Weinberg equation, the proportion of the population that is homozygous dominant can be calculated using the term p². The Hardy-Weinberg principle helps biologists understand the genetic structure of a population in equilibrium.

In this case, to find the percentage of the population that is homozygous dominant, we square the frequency of the dominant allele p (0.8), which results in 0.64 or 64%. Therefore, 64% of the population would be expected to be homozygous dominant (AA).