Final answer:
The Q wave represents the depolarization of the interventricular septum and is the first deflection of a normal QRS complex.
Step-by-step explanation:
The Q wave represents the depolarization of the interventricular septum, which is activated from left to right. In lead II, the direction of the current flow is almost perpendicular to it, and more current is moving away from the positive electrode than is moving toward it. In lead MCL1, depolarization of the interventricular septum will appear as a small, upright R wave. In this lead, this is the first deflection of a normal QRS complex.