Question

What is the end behavior of function h(t)=2(1–3)^2 ?

a) As t approaches [infinity][infinity], h(t) approaches 0.
b) As t approaches [infinity][infinity], h(t) approaches 2.
c) As t approaches [infinity][infinity], h(t) approaches −[infinity].
d) As t approaches [infinity][infinity], h(t) approaches [infinity].

Answer 1

The function h(t)=2(1−3)^2 is a constant function with a value of 8 regardless of the value of t, even as t approaches infinity.

This correct answer b

Step-by-step explanation:

The end behavior of the function h(t)=2(1−3)^2 does not depend on the variable t, because the function is a constant.

The expression (1−3)^2 is a constant equal to 4, and when multiplied by 2, the function h(t) equals 8 for all values of t.

Therefore, no matter what value t approaches, including infinity, h(t) will always be 8.

The correct answer is therefore: As t approaches infinity, h(t) approaches 8, which was not listed among the given options.