Final answer:
To find the values of C and D in the equation C×2×(3×D)=36, we simplified the equation and found multiple pairs that satisfy the condition. However, according to the options provided, the correct pair is C=2 and D=6.
Step-by-step explanation:
We need to find the values of C and D that satisfy the equation C×2×(3×D)=36. To do this, let's simplify the equation:
Step 1: Rewrite the equation as C×6×D = 36 because 2×(3×D) can be simplified to 6×D.
Step 2: Divide both sides by 6 to isolate C×D, which gives C×D = 36/6 = 6.
Step 3: Now we need to find the values of C and D that when multiplied give us 6. The possible pairs (C, D) are (1, 6), (2, 3), (3, 2), and (6, 1).
Checking each pair against our original equation:
- For (1, 6): 1×2×(3×6) = 2×18 = 36, which is correct.
- For (2, 3): 2×2×(3×3) = 4×9 = 36, which is correct.
- For (3, 2): 3×2×(3×2) = 6×6 = 36, which is correct.
- For (6, 1): 6×2×(3×1) = 12×3 = 36, which is correct.
All the pairs are valid solutions for the equation. However as per the given options (A, B, C, D), the only one that matches the pairs we found is option B: C=2, D=6.