Question

Write a C++ function that accepts an integer number and prints the even factor sum of the number.

Answer 1

A C++ function to print the even factor sum of a number iterates through even numbers, checks if they are factors, sums them, and prints the result. The function requires the iostream header for output.

Step-by-step explanation:

C++ Function to Calculate Even Factor Sum

To write a C++ function that accepts an integer number and prints the even factor sum of the number, you need to iterate through all possible even factors of the given number and add them up. Here is a simple implementation of such a function:

void printEvenFactorSum(int number) {
int sum = 0;
for (int i = 2; i <= number; i += 2) {
if (number % i == 0) {
sum += i;
}
}
std::cout << "The even factor sum is: " << sum << std::endl;
}

This function starts a loop from 2 (the smallest even number) and then increments by 2 each time to ensure that only even numbers are checked. If an even number is a factor (i.e., the number divides evenly with no remainder), it is added to the sum. The resulting sum is then printed to the console.

Note: To use this function, you must include the iostream header at the beginning of your code with #include <iostream> for printing the results.