Final answer:
By dividing the total charge (789.8 C) by the charge per electron (-1.6 × 10-19 C), the number of electrons transferred is 4.93625 × 1021. However, this answer does not match any of the provided options, indicating a potential error in the question or options.
Step-by-step explanation:
The question asks how many electrons were transferred if the total charge of a process is 789.8 C. To find this, we use the fact that the charge of one electron is -1.6 × 10-19 C. By dividing the total charge by the charge of one electron, we can find the number of electrons transferred:
- First, write down the charge of one electron, which is -1.6 × 10-19 C.
- Then, divide the total charge (789.8 C) by the charge of one electron.
- The calculation will be 789.8 C ÷ 1.6 × 10-19 C/electron = 4.93625 × 1021 electrons.
Since the possible answers are in simpler figures, we see that none of the given options (a, b, c, d) match the calculated value. The closest option in order would be (c) 1,579.6, but this is not correct. Thus, there seems to be a mistake in the question or the provided options, and none of them represent the correct number of electrons transferred for a total charge of 789.8 C.