2 Answers

Nebuch · Answer 1 · 2022-12-19T05:40:13+0000

Answer:

Explanation:

Sine doesn't have an inverse, until you restrict the domain to -pi/2 to pi/2. If you don't restrict the domain, then the inverse doesn't exist. Im going to assume the domain is restricted.

Switch the x and y values

$x= \pi/4+ \sin(y)$

Subtract pi/4 on both sides

$x- \pi/4= \sin(y)$

Take the arcsine of both sides

$\arcsin(x- \pi/4)=y$

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