Final answer:
The approximate energy of a photon with a frequency of 4 x 10^14 Hz is 2.65 × 10^-41 J.
Step-by-step explanation:
To calculate the approximate energy of a photon with a frequency of 4 x 10^14 Hz, we can use Planck's constant (h) and the equation E = hf, where E is the energy, h is Planck's constant (6.626 × 10^-34 J·s), and f is the frequency. Plugging in the values, we get: E = (6.626 × 10^-34 J·s) × (4 x 10^14 Hz) = 2.65 × 10^-41 J.