How many milliliters of 10.5 M HCl(aq) are needed to prepare 160.0 mL of 1.00 M HCl(aq)?V=mL

NYRecursion asked Apr 7, 2023

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NYRecursion asked Apr 7, 2023

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15 votes

So,

We could use the following equation:

M1 and M2 represent the initial and final concentrations and V1 and V2 represent the initial and final volumes respectively.

Replacing our values:

Therefore, 15.2380mL are required.

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