Question

An oersted agent has 3 houses for sale, the prices of the houses were in the ratio 6:2:3, and the cheapest house was priced at $240,000. What were the prices of the other 2 houses?

a) $720,000, $240,000
b) $480,000, $160,000
c) $360,000, $120,000
d) $600,000, $200,000

Answer 1

By dividing the price of the cheapest house by its associated ratio number, we find that one part of the ratio is $120,000. Multiplying this by the other ratio numbers yields the prices of the remaining houses: $720,000 and $360,000.

Step-by-step explanation:

The student asked about the prices of houses on sale with a given ratio of 6:2:3, where the cheapest house was priced at $240,000. To find the prices of the other two houses, we will first determine the value of one part of the ratio by dividing the price of the cheapest house by the ratio number associated with it (which is 2). Consequently, one part of the ratio equals $120,000. Now, to find the prices of the other two houses, we simply multiply the corresponding ratio numbers by the price of one part.

The price of the second house (with the ratio 6) is $120,000 x 6 = $720,000.

The price of the third house (with the ratio 3) is $120,000 x 3 = $360,000.