Question

What is the output? float x = 007; printf("%f", x);

a. 007.000000
b. None of the above
c. 7.000000
d. 7
e. 007

Answer 1

The output of the given code 'float x = 007; printf("%f", x);' is '7.000000', where leading zeros in the variable initialization are ignored and the float is displayed with six decimal places.

Step-by-step explanation:

The correct answer to the question 'What is the output? float x = 007; printf("%f", x);' is c. 7.000000. When the float variable 'x' is initialized to '007', it is equivalent to writing '7' because leading zeros do not affect the value of the number. The printf function with the '%f' format specifier prints a floating-point number in decimal notation, and by default, it displays six digits after the decimal point, hence the output will be '7.000000'.