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What is the expected value when rolling a fair 12-sided die? OLES OCT

What is the expected value when rolling a fair 12-sided die? OLES OCT-example-1
User MorganTN
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1 Answer

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The numbers on a 12 sided die are 1,2,3,4,5,6,7,8,9,10,11,12

Each side has a 1/12 change of comming up

We take the number on the side and multiply by the probability and sum them

1 * 1/12 + 2 * 1/12 + 3 * 1/12 + 4 * 1/12 + 5 * 1/12 + 6 + 1/12 + 7 * 1/12 + 8 + 1/12 + 9 * 1/12 + 10 * 1/12 + 11 * 1/12 + 12* 1/12

This is equal to

1/12 + 2/12 + 3/12 + 4/12 + 5/12 + 6/12 + 7/12 + 8/12 + 9/12 + 10/12 + 11/12 + 12/12

or 78/12

Simplifying

6 6/12

or 6.5

User JLRishe
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