Question

What happens to the graph of y=-2-6z+50z³+45z² - 108z - 108 as z heads toward oo and-oo CAME-y Ami xasz →-00, y →∞ (Bax-x-xasz-, y →∞ *-+8x-+zwx-+*+*30 *****0 **** z *. y

Answer 1

Given:

`y=-x^6-6x^5+50x^3+45x^2-108x-108`

Let's determine the end behaviour.

Let's use the degree and the leading coefficient to find the end behaviour.

The leading coefficient is = -1 (negative value).

The degree is = 6 (even).

Since the leading coefficient is negative and the degree is an even number, the graph will fall to the left and fall to the right.

Therefore, as x approaches infinity, y approaches negative infinity and as x approaches negative infinity, y approaches negative infinity.

• ANSWER:

C. As x ==> ∞, y ==> -∞ as x ==> -∞, y ==> -∞