Question

What is the output? int v1 = 2; int v2 = 5; int res = 6; res = v1++ * v2--; System.out.println("v1: " + v1); System.out.println(); System.out.println(" v2: " + v2 + " res: " + res);

Answer 1

The output after the code execution will display the incremented and decremented values of v1 and v2, along with the multiplied result stored in res. The output will be 'v1: 3', 'v2: 4', and 'res: 10'.

Step-by-step explanation:

The output of the given code block can be determined by understanding the post-increment and post-decrement operators in Java, which are used here. The initial values provided are v1 = 2, v2 = 5, and res = 6. When the multiplication operation res = v1++ * v2-- is performed, the post-increment operator (++) causes v1 to be used first at its current value (2) and then incremented to 3. Similarly, the post-decrement operator (--) causes v2 to be used at its current value (5) and then decremented to 4. The multiplication thus yields res = 2 * 5 which gives res = 10. The final values for v1, v2, and res are 3, 4, and 10 respectively. So the printed output will be:

• v1: 3
• v2: 4 res: 10