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Match each function on the left to all points on the right that would be located on the graph of the function.

A. f(x) = 2x + 2, (0, 2)
B. f(x) = 2x^2 - 2, (2, 0)
C. f(x) = 2x+1, (-1, 0)
D. f(x) = 2, (2, 6)

1 Answer

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Final answer:

Only the point (0, 2) is located on the graph of the corresponding function A (f(x) = 2x + 2). The points (2, 0), (-1, 0), and (2, 6) do not lie on the graphs of their respective functions B, C, and D.

Step-by-step explanation:

To match each function to the given points that would be located on the graph of the function, we must substitute the x-value of each point into the function and see if the resulting y-value matches the one given in the point.

  1. For A. f(x) = 2x + 2, plugging in x = 0 gives us f(0) = 2 * 0 + 2 = 2. Thus, the point (0, 2) is on the graph of function A.
  2. For B. f(x) = 2x^2 - 2, plugging in x = 2 gives us f(2) = 2 * 2^2 - 2 = 8 - 2 = 6. The point (2, 0) is not on the graph of function B because 0 does not equal 6.
  3. For C. f(x) = 2x + 1, plugging in x = -1 gives us f(-1) = 2 * (-1) + 1 = -2 + 1 = -1. The point (-1, 0) is not on the graph because -1 does not equal 0.
  4. For D. f(x) = 2, the function is a constant, so the y-value is always 2 regardless of x. The point (2, 6) is not on the graph of function D because 6 does not equal 2.
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