Final answer:
The jogger is running at a speed of 2.37 m/s. The jogger runs approximately 8.74 km in 99.0 minutes. The time after the jogger covers 4.72x10^4 ft is 3:30 p.m.
Step-by-step explanation:
(A) To convert the jogger's average speed from miles per hour (mi/h) to meters per second (m/s), we need to use conversion factors. Since 1 mile is equal to 1609.34 meters and 1 hour is equal to 3600 seconds, we can convert as follows:
Average speed = 5.30 mi/h * (1609.34 m / 1 mi) * (1 h / 3600 s) = 2.37 m/s (to 3 significant figures)
So, the jogger is running at a speed of 2.37 m/s.
(B) To find the distance the jogger runs in 99.0 minutes, we can use the formula Distance = Speed * Time. First, we convert 99.0 minutes to hours by dividing by 60:
Time = 99.0 min * (1 h / 60 min) = 1.65 h
Then, we can calculate the distance using the average speed:
Distance = 5.30 mi/h * 1.65 h = 8.745 mi ≈ 8.74 km (to 3 significant figures)
Therefore, the jogger runs approximately 8.74 km in 99.0 minutes.
(C) To find the time after the jogger covers 4.72x10^4 ft, we need to convert this distance to meters. Since 1 foot is equal to 0.3048 meters, we can convert as follows:
Distance = 4.72x10^4 ft * 0.3048 m / 1 ft = 14393.76 m
Since the jogger runs at a constant speed, we can use the formula Time = Distance / Speed to find the time taken:
Time = 14393.76 m / 5.30 m/s = 2719.962 s ≈ 2719.96 s
Adding this time to the starting time of 11:15 a.m., we get the new time:
11:15 a.m. + 2719.96 s = 3:30 p.m.
So, the time after the jogger covers 4.72x10^4 ft is 3:30 p.m.