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Find all points on the x-axis units 5 away from the point (1, -3).

a) (6, 0) and (-4, 0)
b) (1, 5) and (1, -8)
c) (6, -3) and (-4, -3)
d) (1, 5) and (1, -8)

User Wallop
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1 Answer

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Final answer:

To find all points on the x-axis that are 5 units away from the point (1, -3), we use the distance formula to calculate the distance between the points. By plugging in the known values and solving for x, we find that the points are (6, 0) and (-4, 0).

Step-by-step explanation:

To find all points on the x-axis that are 5 units away from the point (1, -3), we can use the distance formula. The distance formula is given by:

d = √ ((x2 - x1) ^2 + (y2 - y1) ^2)

Since we want to find points on the x-axis, the y-coordinate of the second point will be 0. Plugging in the known values, we get:

5 = √((x - 1)^2 + (-3 - 0)^2)

Simplifying and solving for x gives us two possible values for x - 6 and -4. Therefore, the points on the x-axis that are 5 units away from (1, -3) are (6, 0) and (-4, 0).

User Zans
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