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44 votes
Find the power dissipation of a 1.5 A lamp operating on a 12 V battery.

User Steve Smith
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1 Answer

21 votes
21 votes

We will have the following:

We recall that power dissipation is given by:


P=IV

Then:


P=(1.5A)(12V)\Rightarrow P=18W

So, the power is 18 Watts.

User Nana Kwame
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