351,238 views
44 votes
44 votes
Find the power dissipation of a 1.5 A lamp operating on a 12 V battery.

User Steve Smith
by
2.7k points

1 Answer

21 votes
21 votes

We will have the following:

We recall that power dissipation is given by:


P=IV

Then:


P=(1.5A)(12V)\Rightarrow P=18W

So, the power is 18 Watts.

User Nana Kwame
by
3.0k points