Final answer:
To make 10L of a 0.1 M aqueous solution of acetic acid, you would need 600.5 grams of acetic acid, calculated using the molarity, the volume of the solution, and the molar mass of acetic acid.
Step-by-step explanation:
To calculate how many grams of acetic acid (C2H4O2) are needed to make 10L of a 0.1 M aqueous solution, we start by using the formula:
Mass = Molarity (M) × Volume (L) × Molecular Weight (g/mol).
Acetic acid has a molecular weight of approximately 60.05 g/mol. Thus, for a 0.1 M solution:
- Molarity (M) = 0.1 mol/L
- Volume (L) = 10 L
- Molecular Weight (g/mol) of acetic acid = 60.05 g/mol
Plugging these values into the formula, we get:
Mass = 0.1 mol/L × 10 L × 60.05 g/mol = 600.5 grams.
This is the amount of acetic acid required to prepare 10L of a 0.1 M solution.