Question

A ball dropped from a height of 4.00m makes a perfectly elastic collision with the ground. Assuming no mechanical energy is lost due to air resistance:

Determine the period of the motion.

A. T=√ (8h/g)

B. T=√ (2h/g)

C. T= √ (h/2g)

D. T=√ (4h/g)

Answer 1

The period of motion for a ball making a perfectly elastic collision with the ground without energy loss is given by T= √(8h/g). For a ball dropped from 4.00 m, the correct option is A. T=√(8h/g).

Step-by-step explanation:

The student has asked to determine the period of motion for a ball dropped from a height of 4.00 m that makes a perfectly elastic collision with the ground, with no energy lost to air resistance. The formula for the period T of a freely falling object that makes an elastic collision with the ground is given by T = 2√(2h/g), where h is the height and g is the acceleration due to gravity. Since the question involves a round-trip motion (dropping and returning to the original height), the correct period for the motion is T= √(8h/g).