Question

The probability of event A and B is P(A) = 0.3 and P(B) = 0.4, respectively. If A and B are mutually exclusive, what is the probability of union between A and B?

Answer 1

The probability of the union between mutually exclusive events A and B is equal to the sum of their individual probabilities.

Step-by-step explanation:

When two events, A and B, are mutually exclusive, it means that they cannot happen at the same time. So, the probability of both A and B occurring together is 0.

In this case, if the probabilities of A and B happening individually are given as P(A) = 0.3 and P(B) = 0.4, respectively, then the probability of either A or B happening (the union of A and B) can be calculated by adding their individual probabilities:

P(A OR B) = P(A) + P(B).

Therefore, the probability of the union between A and B is 0.3 + 0.4 = 0.7.