Question

Solve the quation exactly on 0 less greater than t less greater than 2 phi. solve this: sin t: -1

Answer 1

To answer this question, we have that we need to find the values for t where the tangent function will be equal to zero.

We have that:

`\tan t=0`

And, if we see that the function tangent is equal to:

`\tan t=(\sin t)/(\cos t)`

We need to find, in the interval:

`0\leq t\leq2\pi`

The values for which sin(t) = 0. If we see the unit circle, the points, in this interval, where sin(t) = 0 are t = 0, t = pi, and t = 2*pi.

Therefore, we have that the points for tan(t) = 0 are, therefore (in the given interval):

`\tan t=0,t=0,t=\pi,t=2\pi`