Question

Lightning Flash A lightning flash may transfer up to 18 C of charge through a potential difference of 107 V. How much energy does this involve?

a) 1.926 × 10^3 J
b) 1.926 × 10^4 J
c) 1.926 × 10^5 J
d) 1.926 × 10^6 J

Answer 1

The energy dissipated by a lightning flash with a charge of 18 C through a potential difference of 107 V is 1.926 × 10¹ J, which converts to 1.926 × 10¶ J (option d).

Step-by-step explanation:

To calculate the energy involved when a lightning flash transfers a charge, we use the formula:

Energy (E) = Charge (Q) × Potential difference (V)

Where:

• Charge (Q) is given as 18 C
• Potential difference (V) is given as 107 V

Putting it all together:

E = 18 C × 107 V = 1.926 × 109 J

Answer: (d) 1.926 × 106 J