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A man borrows one hundred and eighty-five thousand naira at six percent compound interest. He pays back forty-five thousand naira at the end of each year. How much does he still owe after his second repayment?

a) ₦45,000

b) ₦90,000

c) ₦94,700

d) ₦141,000

User Chalup
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1 Answer

2 votes

Final answer:

After calculating the balance with compound interest for each year and subtracting the repayments, the man still owes approximately ₦115,166, which does not match any of the provided options.

Step-by-step explanation:

The question involves calculating the remaining balance on a loan after two repayments with compound interest being applied. To solve this, we need to follow the steps of compounding the interest and then subtracting the repayments made at the end of each year.

Initially, the man borrows ₦185,000. After the first year, the compound interest formula will be:

New Balance = Principal × (1 + Rate)Time

After 1 year: ₦185,000 × (1 + 0.06)1 = ₦185,000 × 1.06 = ₦196,100

He then repays ₦45,000, so the new balance after the first repayment is:

₦196,100 - ₦45,000 = ₦151,100

We then apply compound interest again for the second year:

After 2 years: ₦151,100 × (1 + 0.06) = ₦151,100 × 1.06 ≈ ₦160,166

After the second repayment of ₦45,000, the balance is:

₦160,166 - ₦45,000 = ₦115,166

None of the options provided match the correct answer, which is ₦115,166. Therefore, there might be an error in the question or the options given.

User AwokeKnowing
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