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What is the electric potential (in units of Volts) at the position of the red dot, which is 0.2 m from each of these charges?

a) 225 V
b) 450 V
c) 675 V
d) 900 V

User Ukr
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1 Answer

3 votes

Final answer:

The electric potential at a given point due to a single point charge can be calculated using the formula V = kQ/r, but to determine the potential at the red dot's position, the charges' magnitudes and signs are needed, which are not provided in the question.

Step-by-step explanation:

To determine the electric potential at the position of the red dot, which is 0.2 m from each of the charges, we need additional information on the magnitude and sign of the charges involved. The electric potential due to a point charge at a distance 'r' from the charge is given by the equation V = kQ/r, where k is Coulomb's constant (8.99 x 109 Nm2/C2), Q is the charge, and r is the distance from the charge.

Without the values for the charges present at the position of the red dot, we cannot calculate the exact electric potential. However, we can interpret the provided problem examples to discuss general principles. For example, if a certain electric potential isoline graph has isolines every 5.0 V and six of these lines cross a 40 cm path, the magnitude of the average electric field along this path can be found using E = ΔV/Δd, where ΔV is the potential difference and Δd is the distance. In this case, the electric field would be (6 isolines x 5 V/isoline) / 40 cm, converting 40 cm to meters gives us 0.4 m, hence 30 V / 0.4 m = 75 V/m.

Similarly, if we have a fixed charge Q and a charge q moving from a distance ri to rf from Q, the potential difference for these positions would be calculated based on the values provided for Q, q, ri, and rf. Without the specific values and distances, a precise answer cannot be given.

User Lucas Holt
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