Question

Consider the following function: void mystery(int& x, int y) { int a=5 x= y* 4+ (a++), a = 2 * y + 5 y = x + 4 } What is the output of the following C++ statements? int a=2. b=3; mystery(a,b). cout​

Answer 1

The given code defines a function called mystery, and performing a series of operations on two variables x and y.

Step-by-step explanation:

The given code defines a function called mystery which takes two parameters: an int& x and an int y. The function performs a series of operations on these variables. Let's break down the code:

1. int a=5: initializes variable a to 5.

2. x= y* 4+ (a++): multiplies the value of y by 4, adds the value of a (5), and assigns the result to x. After that, a is incremented by 1.

3. a = 2 * y + 5: assigns the value of 2 * y + 5 to a.

4. y = x + 4: assigns the value of x + 4 to y.

In this case, a is a temporary variable that does not affect the output, so we can ignore it. The initial values provided for a and b in the C++ statements are not used in the function. Therefore, the output of the function will depend on the values of a and b passed to it.