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What is an equation for the line that passes through (6,-5) and (-8, 16)?

A. y=3x−14
B. y=−x−1
C.y=x+28
D. y=−x+4

User Neal Xiong
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1 Answer

4 votes

Final answer:

The equation for the line that passes through the points (6, -5) and (-8, 16) is y = 3x - 14.

Step-by-step explanation:

To find the equation of a line that passes through two points, we can use the slope-intercept form of a linear equation: y = mx + b, where m is the slope and b is the y-intercept.

First, we need to find the slope (m) using the formula: m = (y2 - y1)/(x2 - x1). Plugging in the values from the given points, we get: m = (16 - (-5))/(-8 - 6) = 21/14 = 3/2.

Next, we can choose one of the points to substitute into the equation and find the y-intercept (b). Let's use (6, -5): -5 = (3/2)(6) + b. Solving for b, we get b = -5 - 9 = -14.

Therefore, the equation for the line that passes through the points (6, -5) and (-8, 16) is y = (3/2)x - 14. Therefore, the correct answer is A. y = 3x - 14.

User Allence Vakharia
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