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The volume of a cylinder having height twice the radius is 17248 cm³. What minimum square cm of paper is needed to cover the curved surface area of the cylinder?

a) 660 cm²
b) 858 cm²
c) 1075 cm²
d) 1296 cm²

User Sdoca
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1 Answer

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Final answer:

To find the minimum square cm of paper needed to cover the curved surface area of the cylinder, we first need to calculate the curved surface area. Given that the height of the cylinder is twice the radius and the volume is 17248 cm³, we can calculate the value of the radius. Substituting the value of 'r' in the formula for the curved surface area, we find that the minimum square cm of paper needed is approximately 5027 cm².

Step-by-step explanation:

To find the minimum square cm of paper needed to cover the curved surface area of the cylinder, we first need to calculate the curved surface area.

The formula for the curved surface area of a cylinder is:

A = 2πrh

Given that the height of the cylinder is twice the radius and the volume is 17248 cm³, we can calculate the value of the radius.

Let's assume the radius of the cylinder is 'r'.

Since the height is twice the radius, the height can be represented as '2r'.

Given that the volume of the cylinder is 17248 cm³, we can write the equation:

17248 = πr²(2r)

Simplifying the equation, we get:

2πr³ = 17248

Dividing both sides by 2π, we get:

r³ = 8648

Taking the cube root of both sides, we get:

r = 20

Now, substituting the value of 'r' in the formula for the curved surface area, we get:

A = 2πrh = 2π × 20 × 40 = 1600π cm²

Therefore, the minimum square cm of paper needed to cover the curved surface area of the cylinder is approximately 5027 cm².

User Roula
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