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Find the average velocity between t=26 s and t=50 s when the displacement is x=10 m at both ×.

A. 0.1 m/s
B. 0.2 m/s
C. 0.5 m/s
D. 1.0 m/s

1 Answer

6 votes

Final answer:

The average velocity between t=26 s and t=50 s, with a displacement of x=10 m at both times, is 0 m/s since the net displacement is zero, making the options provided incorrect.

Step-by-step explanation:

The student is asking about finding the average velocity of an object when the net displacement is zero over a given time interval. To find the average velocity, you would typically take the net displacement divided by the total time taken. However, since at both t=26 s and t=50 s the position x is 10 m, the net displacement in this time interval is 0 m.

Therefore, regardless of the total distance traveled by the object, if the displacement is 0 m, the average velocity must also be 0 m/s. This is because average velocity is defined as the net displacement divided by the total time interval, and in this case, a displacement of 0 m over any non-zero time interval will result in an average velocity of 0 m/s.

Consequently, the answer is:
A. 0.1 m/s
B. 0.2 m/s
C. 0.5 m/s
D. 1.0 m/s
None of the above options provided are correct. The correct answer is not listed, as the average velocity is actually 0 m/s.

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