Question

The speed of a car traveling along a straight road decreases uniformly from 12.0 m/s to 8.0 m/s over 88.0 m. Calculate the acceleration of the car and the time it takes for the car to travel over 88.0 m.

a) Acceleration = 0.045 m/s², Time = 10 s
b) Acceleration = 0.045 m/s², Time = 20 s
c) Acceleration = 0.090 m/s², Time = 10 s
d) Acceleration = 0.090 m/s², Time = 20 s

Answer 1

The acceleration of the car is 0.045 m/s² and it takes 8.8 seconds to travel 88.0 meters.

Step-by-step explanation:

The acceleration of the car can be calculated using the formula:

acceleration = (final velocity - initial velocity) / time

Given that the car's initial velocity is 12.0 m/s, the final velocity is 8.0 m/s, and the distance traveled is 88.0 m, we can substitute these values into the formula:

acceleration = (8.0 m/s - 12.0 m/s) / (88.0 m)

Calculating this, we get an acceleration of 0.045 m/s².

To calculate the time it takes for the car to travel over 88.0 m, we can use the formula:

time = distance / average velocity

The average velocity can be found by taking the average of the initial and final velocities:

average velocity = (12.0 m/s + 8.0 m/s) / 2 = 10.0 m/s

Substituting this into the formula, we get:

time = 88.0 m / 10.0 m/s = 8.8 s

Therefore, the acceleration of the car is 0.045 m/s² and it takes 8.8 seconds to travel 88.0 meters.