Final answer:
The wavelength of the emitted radiation in an x-ray tube can be calculated using the equation λ = hc/E, where λ is the wavelength, h is the Planck's constant, c is the speed of light, and E is the energy of the photon. Given a potential difference of 10^3 V, the energy of the photon is calculated to be 1.60 x 10^-16 J. Substituting this value into the equation, the wavelength is found to be approximately 1.24 x 10^-12 m.
Step-by-step explanation:
The wavelength of the emitted radiation in an x-ray tube can be calculated using the equation:
λ = hc/E
where λ is the wavelength, h is the Planck's constant (6.63 x 10-34 J·s), c is the speed of light (3.00 x 108 m/s), and E is the energy of the photon.
Given a potential difference of 103 V, we can find the energy of the photon using the equation:
E = qV
where E is the energy, q is the charge of an electron (1.60 x 10-19 C), and V is the potential difference.
Plugging in the values, we get:
E = (1.60 x 10-19 C) * (103 V)
E = 1.60 x 10-16 J
Substituting this value of E into the first equation, we can calculate the wavelength:
λ = (6.63 x 10-34 J·s) * (3.00 x 108 m/s) / (1.60 x 10-16 J)
λ ≈ 1.24 x 10-12 m
Therefore, the wavelength of the emitted radiation is approximately 1.24 x 10-12 m.