Final answer:
The probability density function of a normal variable is a symmetric distribution that is bell-shaped and defined by its mean and variance.
Step-by-step explanation:
The question pertains to the probability density function (PDF) of a normal variable X with mean μ and variance σ^2. A probability density function of a normal or Gaussian distribution has certain characteristics:
- It is a symmetric distribution around its mean.
- Each normal distribution is defined by its mean (μ) and variance (σ^2).
- The shape of the distribution is bell-shaped and continuous, not uniform or discrete.
- The mean, median, and mode of a normal distribution are all equal.
- The area under the curve of a PDF is equal to 1.
Therefore, the correct statement that describes the probability density function of the normal variable X is that it is a symmetric distribution.