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How much is the ring worth in dollars if the cost of silver is $29.85 per ounce, and a pure silver ring displaces a volume of 7mL in a graduated cylinder?

a. $210.24
b. $20.45
c. $598.08
d. $29.85

1 Answer

4 votes

Final answer:

To find the value of a pure silver ring, calculate the ring's mass using its density and volume, convert to ounces, and then multiply by the price per ounce. The value is determined to be $77.33, which is not provided in the given options.

The correct opiton is not given.

Step-by-step explanation:

To determine the value of a pure silver ring in dollars, given the cost of silver per ounce and its displacement volume, we must first calculate the mass of silver using its known density and then convert that into ounces to find the value based on the given price.

The density of silver is 10.49 g/cm³. Since 1 mL is equivalent to 1 cm³, the mass of the silver in the ring can be calculated as follows:

Mass = density × volume

Mass = 10.49 g/cm³ × 7 cm³

Mass = 73.43 grams

Next, convert the mass in grams to ounces, knowing that 1 ounce is approximately 28.35 grams:

73.43 g ÷ 28.35 g/ounce ≈ 2.59 ounces

Multiply the mass in ounces by the cost of silver per ounce to find the total value:

Value = 2.59 ounces × $29.85/ounce

Value = $77.33

Therefore, the value of the silver ring is $77.33, so none of the options provided (a. $210.24, b. $20.45, c. $598.08, d. $29.85) is correct. The closest presented value is option b, but it is still incorrect.

The correct opiton is not given.

User Sami Farhat
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