Question

The sum of 5 consecutive even integers is -90. Find the integers.

a) -20, -18, -16, -14, -12
b) -18, -16, -14, -12, -10
c) -22, -20, -18, -16, -14
d) -24, -22, -20, -18, -16

Answer 1

The sum of the five consecutive even integers that equals -90 is found by setting the middle integer as x and solving 5x = -90, which gives us the integers -22, -20, -18, -16, and -14.

Step-by-step explanation:

To find the 5 consecutive even integers whose sum is -90, we can let the middle integer be x. Thus, the five integers are x-4, x-2, x, x+2, and x+4. The sum of these five integers is:

(x-4) + (x-2) + x + (x+2) + (x+4) = 5x.

Since the sum equals -90, we have:

5x = -90 ⇒ x = -18.

Therefore, the consecutive integers are: -22, -20, -18, -16, and -14.

So the answer is option c): -22, -20, -18, -16, -14.