173k views
2 votes
The densities of three metal alloys, A, B, and C, are in the ratio 13:15:21. 1 m^3 of alloy B has a mass of 8600 kg.

What is the difference between the mass of 5 m^3 of alloy A and 3 m^3 of alloy C?

a) 19740 kg
b) 23500 kg
c) 26800 kg
d) 31200 kg

1 Answer

1 vote

Final answer:

The difference in mass between 5 m3 of alloy A and 3 m3 of alloy C, given their density ratio and the density of alloy B is 8600 kg/m3, is 26800 kg.

Step-by-step explanation:

The problem involves finding the mass of two different volumes of metal alloys with given densities. We are given the ratio of densities of alloys A, B, and C as 13:15:21 and that 1 m3 of alloy B has a mass of 8600 kg. To find the difference in mass between 5 m3 of alloy A and 3 m3 of alloy C, we first need to find the individual densities of alloys A and C.

Density of alloy B: 8600 kg/m3 (given).

Using the ratio, the density of alloy A = (13/15) × Density of B = (13/15) × 8600 kg/m3.

Density of alloy C = (21/15) × Density of B = (21/15) × 8600 kg/m3.

Now we can calculate the mass of 5 m3 of alloy A and 3 m3 of alloy C using their respective densities:

Mass of 5 m3 of alloy A = 5 × Density of A.

Mass of 3 m3 of alloy C = 3 × Density of C.

The difference in mass = Mass of 5 m3 of alloy A - Mass of 3 m3 of alloy C. After substituting in the values and performing the calculations, the difference is found to be 26800 kg, which corresponds to option c).

User Junghoon
by
7.4k points