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If you draw 1 marble then put it back and draw a second marble, then put it back and draw a third marble, what is the probability of picking an orange marble then a yellow marble, then another orange marble? P(O), P(Y), P(O) =

User EdvRusj
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Final answer:

The probability of drawing an orange marble, then a yellow, then another orange with replacement can be calculated if the number of orange marbles is known. It would involve multiplying the individual probabilities of drawing each color marble. Unfortunately, without the number of orange marbles specified, an exact probability cannot be calculated.

Step-by-step explanation:

To calculate the probability of picking an orange marble then a yellow marble, then another orange marble, we need the individual probabilities of drawing each color marble. However, the details provided mention other colors but do not provide the actual number of orange marbles present in the bag. Assuming replacement occurs after each draw, the probabilities remain constant for each draw, similar to the blue marble examples.

If we had the number of orange marbles (let's say x out of a total of y marbles), the probability of drawing an orange marble would be P(O) = x/y. For a yellow marble (of which there are 2 out of the total y), the probability would be P(Y) = 2/y. The overall probability of drawing the sequence O-Y-O would be the product of each individual event's probability: P(OYO) = P(O) × P(Y) × P(O) = (x/y) × (2/y) × (x/y).

Without details on the number of orange marbles, we cannot provide the exact probability.

User Nate Petersen
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