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If you draw 1 marble then put it back and draw a second marble, then put it back and draw a third marble, what is the probability of picking an orange marble, then a yellow marble, then another orange marble? P(O), P(Y), P(O) =

a) P(O) * P(Y) * P(O)
b) P(O) * P(Y) * P(O) * P(Y)
c) P(O) * P(Y) * P(O) * P(O)
d) P(O) * P(Y) * P(O) * P(O) * P(Y)

User Marnix
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1 Answer

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Final answer:

The probability of drawing an orange, then a yellow, then another orange marble with replacement is calculated by multiplying the individual probabilities for each draw, leading to the formula P(O) * P(Y) * P(O).

Step-by-step explanation:

The question asks about the probability of drawing an orange marble, then a yellow marble, then another orange marble in a sequence with replacement. The process of calculating the probability here involves multiplying the probabilities of each event occurring consecutively since the draws are independent events (due to replacement).

To find the correct probability in this scenario, we would use the formula: P(O) * P(Y) * P(O). This is because the marble is replaced after each draw, ensuring the probability of each color does not change between draws.

Therefore, the correct response is: a) P(O) * P(Y) * P(O).

User Paul Lefebvre
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