337,390 views
16 votes
16 votes
A 8 kg block moving to the right at 4 m/s collides with a 5 kg block moving to the left at -9 m/s, and the two stick together. Find the final velocity.

User Alex Dzeshko
by
2.8k points

1 Answer

14 votes
14 votes

Answer:

V = - 1 m/s

Step-by-step explanation:

Given:

m₁ = 8 kg

V₁ = 4 m/s

m₂ = - 9 m/s

__________

V - ?

Law of conservation of momentum for inelastic impact:

m₁·V₁ + m₂·V₂ = (m₁ + m₂)·V

8·4 - 5·(-9) = (8 + 5)·V

- 13 = 13·V

V = - 13 / 13 = - 1 m/s

Sticky bars move to the left at a speed of 1 m/s

User KarlB
by
2.7k points