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Write the equation of a line parallel to 3x+5y=10 which passes through the point (2,2).

a) 3x+5y=10
b) 5x+3y=1
c) 3x−5y=1
d) 5x−3y=4

1 Answer

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Final answer:

The equation of a line parallel to 3x + 5y = 10 that passes through the point (2,2) is found by using the slope of the given line and employing the point-slope form. The resulting equation after simplification and conversion should be 3x + 5y = 30, which does not match any of the provided options.

Step-by-step explanation:

To find the equation of a line parallel to another line, you must first understand that parallel lines have the same slope. The original equation given is 3x + 5y = 10. To find its slope, we can rearrange it into slope-intercept form (y = mx + b), where m is the slope.

Rewriting 3x + 5y = 10 into y = -⅓x + 2, we find that the slope (m) is -⅓. A parallel line will have the same slope but different y-intercept. Now, using the point (2,2), we employ the point-slope form of the equation, y - y1 = m(x - x1), which translates into y - 2 = -⅓(x - 2).

Simplifying, we get: y = -⅓x + ⅓(2) + 2. Simplified further, y = -⅓x + 4 + 2, hence y = -⅓x + 6. Converting back to standard form: 3x + 5y = 3x + 5(-⅓x + 6) = 3x - 3x + 30 = 30. So, the equation is 5y = 30, or 3x + 5y = 30. None of the provided choices match this equation exactly.

User Mayur Agarwal
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