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Find the perimeter of the polygon with the vertices Q(-3, 2), R(1, 2), S(1, -2), and T(-3, -2).

a) 14 units
b) 16 units
c) 18 units
d) 20 units

User Sundiata
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1 Answer

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Final answer:

The perimeter of the polygon with vertices Q(-3, 2), R(1, 2), S(1, -2), and T(-3, -2) is 16 units, calculated by summing up the distances between each pair of adjacent vertices.

Step-by-step explanation:

The question asks us to find the perimeter of a polygon with given vertices. We can treat this polygon as a rectangle, since the x-coordinates of vertices Q and T are the same, and the y-coordinates of vertices Q and R are the same, which suggests the sides are either vertical or horizontal line segments. To calculate the perimeter, we can find the distances between directly connected vertices. The distance between Q and R or between S and T (which are horizontal sides) can be found by subtracting the x-coordinates: |1 - (-3)| = 4 units. Similarly, the distance between R and S or between T and Q (which are vertical sides) is the difference in their y-coordinates: |2 - (-2)| = 4 units. Hence, the total perimeter of the polygon is 2 times the length of the horizontal side plus 2 times the length of the vertical side: P = 2(4) + 2(4) = 16 units, which is option (b).

User Yashu Mittal
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