Question

A scientist makes an acid solution by adding drops of acid to 121 mL of water. The final volume of the acid solution is 1.202 L. Assuming the volume of each drop is 0.05 mL, how many drops were added to the water? About what percent of the solution is acid? Round to the nearest hundredth of a percent.

a. [number of drops]
b. [percent of acid]
c. [both]
d. [none]

Answer 1

The scientist added 21,620 drops of acid to the water. The acid makes up approximately 89.94% of the final solution.

Step-by-step explanation:

To find out how many drops of acid were added to the water to reach a final volume of 1.202 L, we need to calculate the volume of acid added to the initial 121 mL of water. First, convert the final volume from liters to milliliters: 1.202 L = 1202 mL. Subtracting the initial water volume gives us the volume of acid added: 1202 mL - 121 mL = 1081 mL. Then, by dividing this volume by the volume of one drop of acid (0.05 mL), we find the number of drops added: 1081 mL / 0.05 mL per drop = 21620 drops.

To determine the percentage of acid in the solution, we need to divide the volume of the acid by the total volume of the solution and multiply by 100: (1081 mL / 1202 mL) × 100 = 89.9351%, which rounds to 89.94%.

Therefore, the answers are:

• a. Number of drops: 21620
• b. Percent of acid: 89.94%