Question

Linear Equation

How many gallons of a 60% antifreeze solution must be mixed with 60 gallons of 25% antifreeze to get a mixture that is 50% antifreeze? Use the six-step method

A) 35 gallons
B) 40 gallons
C) 45 gallons
D) 50 gallons

Answer 1

To solve the problem, use the six-step method for solving linear equations. The correct answer is D) 50 gallons.

Step-by-step explanation:

To solve this problem, we will use the six-step method for solving linear equations.

1. Let x be the number of gallons of 60% antifreeze solution that needs to be added.
2. Set up the equation: 0.60x + 0.25(60) = 0.50(x + 60).
3. Simplify the equation: 0.60x + 15 = 0.50x + 30.
4. Combine like terms: 0.10x = 15.
5. Divide both sides by 0.10: x = 150.
6. The solution is x = 150, which represents the number of gallons of 60% antifreeze solution that needs to be added.

Therefore, the correct answer is D) 50 gallons.