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A compound tube consists of a steel tube (140mm internal diameter, 160mm external diameter) and an outer brass tube (160mm internal diameter, 180mm external diameter). The two tubes are of the same length and carry an axial load of 900KN. Find the stresses and the load carried by each tube and the amount it shortens. Length of each tube is 140mm. Take E for steel as 20×106 mm220×106mm2.

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Final answer:

To find the stresses, load carried by each tube, and the amount of shortening, one must use formulas that relate these quantities to the elasticity and dimensions of the materials involved in the compound tube system.

Step-by-step explanation:

The question asks to find the stresses and the load carried by each tube of a compound system consisting of a steel and a brass tube, as well as the amount each tube shortens when subjected to an axial load. The question is focused on mechanical engineering concepts, particularly material strength and elastic deformation.

For steel, the modulus of elasticity (E) is given, which allows us to calculate the stress in the steel tube using the formula σ=E* ε, where σ is the stress and ε is the strain. Similarly, the load carried can be determined by the formula P = σ * A, where P is the load and A is the cross-sectional area of the tube. The shortening (deformation) of each tube can be found with the formula δ = P * L / (A * E), where δ is the deformation, L is the length, and E is the modulus of elasticity.

To solve the problem, one needs to calculate the cross-sectional area, apply the formulas, and find the total load shared by both tubes considering their material properties and geometric dimensions.

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